Question

Please please please please please help me

Answer 1

`{x}^(2) + 0x + 1`

Explanation:

`for \: g (fx) \:the \: function \: of \: f \: is \: inserted \: into \: the \: x \: for \: the \: g`

So the eqn becomes

`({x}^(2) - 1) + 2`

AND this equal to

`{x}^(2) + 1`

Hence the variable x has 0 as its coefficient.