Question

a torque of 6Nm is required to accelerate a wheel from rest to 7.5rev/s In a time of 5.0s.find the moment of inertia of the wheel​

Answer 1

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Torque = 6Nm

Angular acceleration= 7.5 revolutions / second

Moment of inertia = ?

Torque = Moment of inertia * Angular acceleration

Therefore , moment of intertia = Torque / Angular acceleration

Moment of inertia = 6 / 7.5 = 0.8 Kgm^2

Moment of inertia of wheel = 0.8 Kgm^2

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