Question

Someone help please

Answer 1

Explanation:

Hey, there!

Here,

`= 4 {x}^(2) - 4x + 1`

`or ,\: ( {2x)}^(2) - 2.2x .1 + 1`

`or ,\: ( {2x - 1)}^(2)`

We got this because,

`( {2x - y)}^(2) = 4 {x}^(2) - 4x + 1`

By using formula,

`( {x - y)}^(2) = {x}^(2) - 2xy + 1`

Hope it helps..

Answer 2

Answer: (x+-0.5)²=0

Explanation:

4x²-4x+1=0

(2x-1)²=0 ⇔ completing the square

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since the question asked for the x should be 1, then we should divide 2x by 2 so to get rid of the 2 in front of the x.

this will change the original equation into: (x+(-0.5))²=0

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You can also directly divide 4 from 4x²-4x+1=0 to get rid off the terms in front of x.

x²-x+0.25=0

(x-0.5)²=0

(x+(-0.5))²=0