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The larger of two consecutive intergers is 7 greater than twice the smaller.find the intergers

1 Answer

1 vote

Answer:

Smaller integer = -6

Larger integer = -5

Explanation:

Let the two consecutive integers =
x and (
x+1)

As per the given statement,

Larger i.e. (
x+1) is 7 greater than twice (
2* x) the smaller integer.

To find:

The value of integers = ?

Solution:

First of all, let us learn about integers.

The integers are of the form (put in increasing order):


-\infty, ...., -3, -2,-1, 0, 1, 2, 3, ...., \infty

and -1 > -2

So the consecutive integers are 1 greater than the smaller.

Therefore, the two integers can be
x, x+1

Now, writing the given condition in the form of an equation:


x+1=2x+7\\\Rightarrow 1-7=2x-x\\\Rightarrow -6=x\\\Rightarrow \bold{x=-6}

So, the smaller integer = -6

Larger integer = -6+1 = -5

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