Question

Two monatomic ideal gases are in thermal equilibrium with each other. Gas A is composed of molecules with mass m while gas B is composed of molecules with mass 4m. The ratio of the average molecular kinetic energy KA / KB is

Answer 1

Answer:
`(K_(A))/(K_(B))` = 1

Step-by-step explanation: Average molecular kinetic energy for monatomic idela gases is given by:

`E=(3)/(2)RT`

where

R is gas constant of ideal gas

T is temperature

Which means kinetic energy depnends only on temperature.

Since gas A and gas B are at the same temperature, kinetic energy will be the same. Therefore:

`(K_(A))/(K_(B))` = 1

Ratio of this average molecular kinetic energy is 1.