Answer:
P( 43 ≤ X ≤ 49) = 0.9545
Explanation:
We are given mean of 46 and a standard deviation of 3
We want to find the percentage of daily phone calls numbering between 43 and 49. This can be written as;
P( 43 ≤ X ≤ 49)
Using the z-formula, we have;
z = (x - μ)/s
This transforms to;
P((43 - 46)/3)) ≤ Z ≤ ((49 - 46)/3))
This gives;
P(-2) ≤ Z ≤ P(2)
From z - table attached, P(-2) = 0.02275 and P(2) = 0.97725
Thus;
P( 43 ≤ X ≤ 49) = 0.97725 - 0.02275
P( 43 ≤ X ≤ 49) = 0.9545