Answer:
Assuming the charged density in the insulated solid sphere of radius 3.1m is 8.8e-9, the electric field at 5.2 meters is 73.1256
.
Step-by-step explanation:
The electric charge linear density is equal to 8.8 x
the radius of the sphere is 3.1m
The magnitude of the electric field at the radius of the sphere equal to 5.2 meters can be calculated with the formula ;
- E = λ / 4πε₀ [ r / α ( α + r ) ]
Solution:
E = 8.8 x
/ 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ]
= 1018.0995 [0.07183]
= 73.1256