Question

A charge (uniform linear density = 8.8 nC/m) lies on a string that is stretched along an x axis from x = 0 to x = 3.1 m. Determine the magnitude of the electric field at x = 5.2 m on the x axis.

Answer 1

answer= 73.1256
`i`

Step-by-step explanation:

The electric charge linear density is equal to 8.8 x
`10^(-9)`

the length of the string is 3.1m

The magnitude of the electric field at the length of the string equal to 5.2 meters can be calculated with the formula ;

- E = λ / 4πε₀ [
`l` / α ( α +

Solution:

E = 8.8 x
`10^(-9)` / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ]
`i`

= 1018.0995 [0.07183]
`i`

= 73.1256
`i`