Question

at 89 ∘C∘C , where [Fe2+]=[Fe2+]= 3.60 MM and [Mg2+]=[Mg2+]= 0.310 MM . Part A What is the value for the reaction quotient, QQQ, for the cell?

Answer 1

8.6×10^-2

Step-by-step explanation:

The reaction is;

Mg(s) + Fe^2+(aq) -----> Mg^2+(aq) + Fe(s)

This implies that;

Q = [Mg^2+]/[Fe^2+]

But;

[Fe2+]= 3.60 M

[Mg2+]= 0.310 M

Q= [0.310 M]/[3.60 M]

Q= 0.086

Q= 8.6×10^-2