Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Answer 1

2.7 in²

Explanation:

Given that ∆BAC ~ is similar to ∆EDF, the ratio of the area of ∆BAC to the area of ∆EDF = the square of the ratio of their corresponding sides.

Thus, let x be the area of ∆EDF

`(6)/(x) = ((3)/(2))^2`

`(6)/(x) = (9)/(4)`

Cross multiply

`x*9 = 4*6`

`9x = 24`

`(9x)/(9) = (24)/(9)`

`x = 2.67`

Area of ∆EDF = 2.7 in²