Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Answer 1

2.7 in²

Explanation:

Given:

∆BAC ~ ∆EDF

Area of BAC = 6 in²

EF = 2 in

BC = 3 in

Required:

Area of ∆EDF

SOLUTION:

Let x = area of ∆EDF

`(6 in^2)/(x) = ((3 in)/(2 in))^2` (theorem of area of similar triangles)

`(6 in^2)/(x) = ((3 in)/(2 in))^2`

`(6)/(x) = (9)/(4)`

Cross multiply:

`6*4 = 9*x`

`24 = 9x`

Divide both sides by 9

`(24)/(9) = x`

`2.67 = x`

Area of ∆EDF = 2.7 in²