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A child stands on the edge of a merry-go-round of radius 1.63 m which is rotating at 2.13 rad/s. The merry-go-round then slows down to a stop in 26.9 s. While coming to a stop, how many revolutions will
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A child stands on the edge of a merry-go-round of radius 1.63 m which is rotating at 2.13 rad/s.

The merry-go-round then slows down to a stop in 26.9 s.
While coming to a stop, how many revolutions will the merry-go-round make?

User Skirsch
by
4.5k points

1 Answer

11 votes

Answer:

9

Step-by-step explanation:

2.13 rad/s * 26.9 sec

2.13 * 26.9

57.297

3282.88 deg / 360 deg = 9.12

It makes 9 complete revolutoins

A child stands on the edge of a merry-go-round of radius 1.63 m which is rotating-example-1
User David Keaveny
by
4.8k points
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