Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Answer 1

2.7 in²

Explanation:

Since ∆BAC and ∆EDF are similar, therefore, the ratio of their area = square of the ratio of their corresponding side lengths.

Thus, if area of ∆EDF = x, area of ∆BAC = 6 in², EF = 2 in, BC = 3 in, therefore:

`(6)/(x) = ((3)/(2))^2`

`(6)/(x) = (1.5)^2`

`(6)/(x) = 2.25`

`(6)/(x)*x = 2.25*x`

`6 = 2.25x`

`(6)/(2.25) = (2.25x)/(2.25)`

`2.67 = x`

`x = 2.7 in^2` (nearest tenth)