Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Answer 1

2.7 in²

Explanation:

Area of ∆BAC : ∆Area of EDF = BC² : EF² (based on the area of similar triangles theorem)

Thus:

`6 in^2 : x in^2 = (3 in)^2 : (2 in)^2`

`(6)/(x) = (3^2)/(2^2)`

`(6)/(x) = 2.25`

`(6)/(x)*x = 2.25*x`

`6 = 2.25x`

`(6)/(2.25) = (2.25x)/(2.25)`

`2.67 = x`

Area of ∆EDF = 2.7 in²