Question

Assume that a random sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.

Answer 1

Margin of Error = z∝/2 * Standard Error

Explanation:

The formula for standard error is given by

SE =
`\sqrt{(pq)/(n) }`

Where p is the probability or proportion of success q=1-p and n is the number of trials or samples.

Now Margin of Error is given by

ME = z∝/2 * Standard Error

The confidence level is used to estimate the value of alpha.

For example 90% confidence means alpha= 1-0.9= 0.1 and alpha by 2 would be 0.05 . So the value for alpha by 2 would be 1.96