Question

A soft drink contains 63 g of sugar in 378 g of H2O. What is the concentration of sugar in the soft drink in mass percent

Answer 1

`\% m/m= 14.3\%`

Step-by-step explanation:

Hello,

In this case, the by mass percent is computed as shown below:

`\% m/m=(m_(solute))/(m_(solute)+m_(solvent)) *100\%`

Whereas the solute is the sugar and the solvent the water, therefore, the concentration results:

`\% m/m=(63g)/(63g+378g) *100\%\\\\\% m/m= 14.3\%`

Best regards.