Question

If the processor has 32 address lines in its address bus; i.e. 32-bit address range, what is its address space or range; i.e. what is the smallest and largest address that can be represented

Answer 1

The answer is "0 to 4294967295"

Step-by-step explanation:

Given bit:

32 bits

Calculating smallest and largest bits:

In any processor, it works only on the 0 and 1 bit and it also stores 0 and 1 values. so, the smallest address in bit value is= 0 and the largest bit value can be defined as follows:

largest address value in bits:

`\Longrightarrow 2^(32)-1\\\\\Longrightarrow 4294967296 -1\\\\\Longrightarrow 4294967295\\\\`

smallest address= 0

largest address = 4294967295