Answer:
The percentage error in quantity P is 19%.
Step-by-step explanation:
It is given that,
A physical quantity P is related to four observables a, b and c as follows:
![P=(a^3b^2)/(c^4)](https://img.qammunity.org/2021/formulas/physics/high-school/oiy4ijp29fqr5u9rwj6z4c1xps3g6cwj8x.png)
The percentage errors of measurements in a, b and c are 1%, 4% and 2% respectively.
We need to find the percentage error in quantity P. It is given by :
![(\Delta P)/(P)* 100=(3* (\Delta a)/(a)+2* (\Delta b)/(b)+4* (\Delta c)/(c))\\\\=3* 1+2* 4+4* 2\\\\(\Delta P)/(P)* 100=19\%](https://img.qammunity.org/2021/formulas/physics/high-school/bz609316j6zbuko3t8zr4w98n87c4e9dqm.png)
So, the percentage error in quantity P is 19%.