Answer:
![\large \boxed{350}](https://img.qammunity.org/2021/formulas/chemistry/high-school/tq0gbp8gonrse99vzy338typ09qirtb7ob.png)
Step-by-step explanation:
In multiplication and division problems, the answer can have no more significant figures than the number with the fewest significant figures.
My calculator gives the result:
![(4568)/(13) = 351.3846154](https://img.qammunity.org/2021/formulas/chemistry/high-school/mvpm838zypmmg7t6klox8op5xw3z1zsgsl.png)
4658 has four significant figures.
13 has two significant figures.
You must round to two significant figures.
That is, you drop all the digits to the right of the 5 — the red line in Fig. 1 below. You are rounding to the nearest ten.
To round a number to the nearest ten, you look at the number in the ones place (1). See Fig. 2.
If the number to be dropped — the digit in the ones place — is less than 5, you drop the digit in the ones place (Fig. 3). It becomes a zero.
The number in the tens place is a trailing zero. It is not significant.
![\text{The quotient of $(4658)/(13)$ is $\large \boxed{\mathbf{350}}$}](https://img.qammunity.org/2021/formulas/chemistry/high-school/prawwv6pv0l1gm1uy39hu6l5alj6414a2b.png)