Question

The gas with an initial volume of 24.0 L at a pressure of 565 torr is compressed until the volume is 16.0 L. What is the final pressure of the gas, assuming the temperature and amount of gas does not change

Answer 1

848 torr

Step-by-step explanation:

The only variables are the pressure and the volume, so we can use Boyle's Law.

p₁V₁ = p₂V₂

Data:

p₁ = 565 torr; V₁ = 24.0 L

p₂ = ?; V₂ = 16.0 L

Calculations:

`\begin{array}{rcl}p_(1)V_(1) & = & p_(2)V_(2)\\\text{565 torr} * \text{24.0 L} & = & p_(2) * \text{16.0 L}\\\text{13 560 torr} & = & 16.0p_(2)\\p_(2) & = & \frac{\text{13 560 torr}}{16.0}\\\\& = &\textbf{848 torr}\\\end{array}\\\text{The final pressure of the gas is $\large \boxed{\textbf{848 torr}}$}`