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Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a confidence level of 98%, and use the results from a prior Harris poll that gave a confidence interval of (0.44, 0.51) for the proportion of Democrats who have a sibling.

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5 votes

Answer:

The minimum sample size is
n =135

Explanation:

From the question we are told that

The confidence interval is
( lower \ limit = \ 0.44,\ \ \ upper \ limit = \ 0.51)

The margin of error is
E = 0.1

Generally the sample proportion can be mathematically evaluated as


\r p = ( upper \ limit + lower \ limit )/(2)


\r p = ( 0.51 + 0.44)/(2)


\r p = 0.475

Given that the confidence level is 98% then the level of significance can be mathematically evaluated as


\alpha = 100 - 98


\alpha = 2\%


\alpha =0.02

Next we obtain the critical value of
(\alpha )/(2) from the normal distribution table

The value is


Z_{(\alpha )/(2) } = 2.33

Generally the minimum sample size is evaluated as


n =[ \frac { Z_{(\alpha )/(2) }}{E} ]^2 * \r p (1- \r p )


n =[ \frac { 2.33}{0.1} ]^2 * 0.475(1- 0.475 )


n =135

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