PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK

Question

asked Apr 28, 2021 58.7k views

1 Answer

Tom Jenkin · Answer 1 · 2021-05-05T07:17:34+0000

Answer:

$\huge\boxed{9}$

Explanation:

$\sf (2^8 * 3^(-5) * 6^0)^(-2 ) ((3^(-2))/(2^3) )^4*2^(28)$

Rule of exponents
a^0 = 1 ,
1/a^m = a^(-m)

=>
$\sf 2^(8*-2) * 3 ^(-5*-2) * 3 ^(-2)* 2^(-3*4) * 2^(28)$

=>
$\sf 2 ^ {-16} * 3^(10) * 3^(-8) * 2 ^(-12)* 2^(28)$

Combining same bases

=>
$\sf 2 ^ {-16} * 2 ^(-12)* 2^(28)* 3^(10) * 3^(-8)$

When bases are same , powers are to be added

=>
$\sf 2 ^(-16-12+28) * 3^(10-8)$

=>
$\sf 2^(-28+28) * 3^2$

=>
$\sf 2^0 * 3^2$

=>
$\sf 3^2$

=> 9