Answer:
![Probability = 0.35](https://img.qammunity.org/2021/formulas/mathematics/college/64ckydh6ec793ruyvqza7uom2sfuj0u2a0.png)
Explanation:
Given
Probability of success free throw = 90%
Number of throw = 10
Required
Determine the probability of 10 consecutive free throws
Let p represents the given probability
![p = 90\%](https://img.qammunity.org/2021/formulas/mathematics/college/9qu7wigljwmjv1u7k3br8ls99k1mrcww5o.png)
Convert to decimal
![p = 0.9](https://img.qammunity.org/2021/formulas/mathematics/college/8ppcucp81rqvuu80ttloe47gsau07336mq.png)
Let n represents the number of throw
![n = 10](https://img.qammunity.org/2021/formulas/mathematics/college/xejj4jniyiwc8a9rmenb3rznbf23wm5em1.png)
Provided that each throw is independent;
The probability of n consecutive free throw is
![p^n](https://img.qammunity.org/2021/formulas/mathematics/college/zcwmdcu0ucsuzrcnebx2rpi09v7qi1k3jb.png)
Substitute 0.9 for p and 10 for n
![Probability = 0.9^(10)](https://img.qammunity.org/2021/formulas/mathematics/college/7tlz0j82db5zr6fg40gbj7vt1wgjhvbx90.png)
![Probability = 0.3486784401](https://img.qammunity.org/2021/formulas/mathematics/college/a2wy7pw3rutb30gv2y16h67idlgdmatzve.png)
(Approximated)