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A particular celestial body orbits at a particular speed. For every two orbits it makes, another celestial body orbits three times. This orbital resonance would correspond to which musical interval?

User Georgedyer
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Final answer:

The 2:3 orbital resonance of two celestial bodies corresponds to a musical fifth interval, which is prominent in both astronomy and music theory and closely linked to Kepler's third law of planetary motion.

Step-by-step explanation:

The celestial bodies you've mentioned exhibit a specific orbital resonance of 2:3. This corresponds to a musical fifth interval, where the frequency ratio is 2:3. This concept is related to both music and astronomy, linking the physics of celestial motion to harmonic sounds. In music, an interval is the difference in pitch between two sounds. If two celestial bodies have an orbital resonance such that in the same period, one orbits twice while the other orbits three times, their motion creates a pattern analogous to a fifth interval in music.

Considering Kepler's laws of planetary motion, particularly the third law, which states the ratio of the squares of the periods of any two orbiting bodies is equal to the ratio of the cubes of their semimajor axes, we can understand the relationship between the orbital periods of these celestial bodies. However, in this scenario, we do not need to calculate the actual periods since we are dealing with their ratio, which directly resonates with the musical interval.

User Yossi Farjoun
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Answer:

Step-by-step explanation:

frequency of first body f₁ = 2 / T where T is time taken by it for making two orbits

frequency of second body f₂ = 3 / T

ration of two frequency

f₁ / f₂ = 2 / 3

This ratio is called perfect fifth in musical interval .

User Yehan
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