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4 votes
Solve the following equation
3x + 5 = 17

Geometry pre

User Spudwaffle
by
8.5k points

2 Answers

3 votes

Answer:


\boxed{ \boxed{ \bold{4}}}

Explanation:


\mathsf{3x + 5 = 17}

Move constant to R.H.S and change it's sign


\mathsf{3x = 17 - 5}

Subtract 5 from 17


\mathsf{3x = 12}

Divide both sides of the equation by 3


\mathsf{ (3x)/(3) = (12)/(3) }

Calculate


\mathsf{x = 4}

Hope I helped!

Best regards!

User Alloy
by
8.2k points
3 votes

Answer:

x = 4

Explanation:

First, we need to get the 3x by itself on the left. To do this, we subtract 5 from both sides. 3x + 5 - 5 = 17 - 5; 3x = 12. Now, to find x, we divide both sides by 3 to get 3x/3=12/3; x = 4

User Sam Meldrum
by
8.0k points

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