Question

A large reflecting telescope has an objective mirror with a 14.0 m radius of curvature. What angular magnification in multiples does it produce when a 3.25 m focal length eyepiece is used? ✕

Answer 1

The magnification is
`m = -2.15`

Step-by-step explanation:

From the question we are told that

The radius is
`r = 14.0 \ m`

The focal length eyepiece is
`f_e = 3.25 \ m`

Generally the objective focal length is mathematically represented as

`f_o = (r)/(2)`

=>
`f_o = (14)/(2)`

=>
`f_o = 7 \ m`

The magnification is mathematically represented as

`m = - (f_o )/(f_e )`

=>
`m = - (7 )/( 3.25 )`

=>
`m = -2.15`