Question

In the lab , you have an electric field with a strength of 1,860 N/C. If the force on a particle with an unknown charge is 0.02796 N, what is the value of the charge on this particle.

Answer 1

The charge is
`q = 1.50 *10^(-5) \ C`

Step-by-step explanation:

From the question we are told that

The electric field strength is
`E = 1860 \ N/C`

The force is
`F = 0.02796 \ N`

Generally the charge on this particle is mathematically represented as

`q = (F)/(E)`

=>
`q = (0.02796)/( 1860)`

=>
`q = 1.50 *10^(-5) \ C`