Given the function, Calculate the following values:

asked Aug 26, 2021 113k views

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Answer:

$f(-2)=33\\f(-1)=12\\f(0)=1\\f(1)=0\\f(2)=9$

Explanation:

$f(x)=5x^(2) -6x+1\\f(-2)=5(-2)^(2) -6(-2)+1\\f(-2)=5(4)+12+1\\f(-2)=20+13\\f(-2)=33$

$f(x)=5x^(2)-6x+1\\f(-1)=5(-1)^(2) -6(-1)+1\\f(-1)=5(1)+6+1\\f(-1)=5+7\\f(-1)=12$

$f(x)=5x^(2)-6x+1\\f(0)=5(0)^(2)-6(0)+1\\f(0)=5(0)-0+1\\f(0)=0+1\\f(0)=1$

$f(x)=5x^(2)-6x+1\\f(1)=5(1)^(2)-6(1)+1\\f(1)=5(1)-6+1\\f(1)=5-5\\f(1)=0$

$f(x)=5x^(2)-6x+1\\f(2)=5(2)^(2)-6(2)+1\\f(2)=5(4)-12+1\\f(2)=20-11\\f(2)=9$

Bix answered Sep 1, 2021

by Bix

7.8k points

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