69.8k views
3 votes
A car is going 8 meters per second on an access road into a highway

and then accelerates at 1.8 meters per second squared for 7.2
seconds. How fast is it then going?

User Sal Aldana
by
3.4k points

1 Answer

3 votes

Answer:

20.96 m/s^2 (or 21)

Step-by-step explanation:

Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

Then, we know the acceleration, which is 1.8 m/s/s

We also know the time, 7.2 second.

Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.

(final velocity - initial velocity) = time * acceleration

final velocity = time*acceleration + initial velocity

After plugging the found values in, we get 20.96 m/s/s, or 21 m/s

User Paolo Maresca
by
3.7k points