Answer: a) 0.1095 b) 0.0095
Explanation:
Given : The deck for a card game contains 30 cards.
10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards.
Each player is randomly dealt a five-card hand.
Number of ways to choose 5 cards out of 30 =
![C(30,5)=(30!)/(5!25!)=142506](https://img.qammunity.org/2021/formulas/mathematics/college/98neallpf6emnf4kzwxta0sf8xmumwe2vl.png)
a) Cards other than wild card = 30-4=26
Number of ways to choose exactly two wild cards =
![C(26,3)*C(4,2)](https://img.qammunity.org/2021/formulas/mathematics/college/6jfeuva5vziy3pa28jczzc37p0i6pcja9w.png)
![=(26!)/(3!23!)*(4!)/(2!2!)\\\\=15600](https://img.qammunity.org/2021/formulas/mathematics/college/vhcxy8fnphrrwll6ejtzg4sd9547vedsu7.png)
Probability that a hand will contain exactly two wild cards =
![(15600)/(142506)=0.1095](https://img.qammunity.org/2021/formulas/mathematics/college/jidcoahktpf87l3kpk5ytb9gwt5krax38t.png)
b) Number of ways to choose two wild cards, two red cards, and one blue cards =
![C(4,2)* C(10,2)* C(5,1)](https://img.qammunity.org/2021/formulas/mathematics/college/ohfxzjun02qqi3bv2yukzndn816h01fr7n.png)
![=(4!)/(2!2!)*(10!)/(2!8!)*5=1350](https://img.qammunity.org/2021/formulas/mathematics/college/f3fi7tfrga00oddby3swjatdubd4nvduli.png)
Probability that a hand will contain two wild cards, two red cards, and one blue cards =
![(1350)/(142506)=0.0095](https://img.qammunity.org/2021/formulas/mathematics/college/ud2lql9vdm47jcc4109dbvqm0pmb23xjcp.png)