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The deck for a card game contains 30 cards. 10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards. Each player is randomly dealt a five-card hand. a) What is the probability that a hand will contain exactly two wild cards? b) What is the probability that a hand will contain two wild cards, two red cards, and one blue cards?

User Russian
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1 Answer

2 votes

Answer: a) 0.1095 b) 0.0095

Explanation:

Given : The deck for a card game contains 30 cards.

10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards.

Each player is randomly dealt a five-card hand.

Number of ways to choose 5 cards out of 30 =
C(30,5)=(30!)/(5!25!)=142506

a) Cards other than wild card = 30-4=26

Number of ways to choose exactly two wild cards =
C(26,3)*C(4,2)


=(26!)/(3!23!)*(4!)/(2!2!)\\\\=15600

Probability that a hand will contain exactly two wild cards =
(15600)/(142506)=0.1095

b) Number of ways to choose two wild cards, two red cards, and one blue cards =
C(4,2)* C(10,2)* C(5,1)


=(4!)/(2!2!)*(10!)/(2!8!)*5=1350

Probability that a hand will contain two wild cards, two red cards, and one blue cards =
(1350)/(142506)=0.0095

User Alireza Eliaderani
by
5.1k points
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