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If you run a particular reaction, and in theory it was supposed to yield 50.0 grams of product, and the percent yield is 75%, how many grams did you actually end up with?

2 Answers

6 votes

Final answer:

To calculate the actual yield of a reaction with a theoretical yield of 50.0 grams and a percent yield of 75%, you would end up with an actual yield of 37.5 grams.

Step-by-step explanation:

If the theoretical yield of a reaction is supposed to be 50.0 grams and the percent yield is 75%, you can calculate the actual yield using the percent yield formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

To find the actual yield, rearrange this formula:

Actual Yield = (Percent Yield / 100%) x Theoretical Yield

So, the actual yield will be:

Actual Yield = (75% / 100%) x 50.0 g = 0.75 x 50.0 g = 37.5 g

Therefore, the actual yield you would end up with is 37.5 grams.

User Nicola Mori
by
6.5k points
4 votes

Answer:

37.5 grams

Step-by-step explanation:

The percent yield shows how much of the reactant have been converted to product. The percent yield is the ratio of actual yield to theoretical yield multiplied by 100%. It is given by the formula:

%yield = Actual yield/ theoretical yield × 100%

Given that theoretical yield = 50 grams and the percent yield is 75%.

Using the formula and substituting:

75% = Actual yield/ 50 g × 100%

75% / 100% = Actual yield / 50 g

0.75 = Actual yield / 50 g

Actual yield = 0.75 × 50 g

Actual yield = 37.5 grams

User Nrc
by
6.4k points