Question

In the reaction of Zn(s) + 2HCl (aq) Imported Asset ZnCl2 (aq) + H2 (g), if [HCl] increases from 2.6 M to 8.2 M:

The rate at which Zn disappears decreases.
The rate at which H2 appears decreases.
The rate at which ZnCl2 appears increases.
The concentration of Zn (s) also increases.

Answer 1

The rate at which ZnCl2 appears increases.

Step-by-step explanation:

Hello,

In this case, the reaction is:

`Zn(s) + 2HCl (aq) \rightarrow ZnCl_2 (aq) + H_2 (g)`

Therefore, the law of rate proportions is:

`(1)/(-1)r_(Zn)= (1)/(-2)r_(HCl)= (1)/(1)r_(ZnCl_2)= (1)/(1)r_(H_2)}`

In such a way, since the concentration of hydrochloric acid is increasing The rate at which ZnCl2 appears increases, because the addition of a reactant is directly related with the products formation due to the fact that more reactant will yield more product.

Best regards.