Question

On a coordinate plane, a triangle has points (negative 5, 1), (2, 1), (2, negative 1).

Use the drop downs to answer the following questions about the distance between the points (−5, 1) and (2, −1).

What is the distance of the horizontal leg?

What is the distance of the vertical leg?

Use the Pythagorean theorem. What is the distance between the two points?

Answer 1

The answer are 7, 2 and 53

Explanation:

Answer 2

The answer is below

Explanation:

The points of the triangle are (- 5, 1), (2, 1), (2, - 1). The distance between two points is given by:

`Distance=√((x_2-x_1)^2+(y_2-y_1)^2)`

The horizontal leg is formed by points with the same y axis. Therefore the points that make up the horizontal leg is (- 5, 1), (2, 1). The Distance of the horizontal leg is:

`Horizontal\ leg=√((2-(-5))^2+(1-1)^2)=√(7^2+0)=7\ units`

The vertical leg is formed by points with the same x axis. Therefore the points that make up the vertical leg is (2 1), (2, 1-). The Distance of the vertical leg is:

`Vertical\ leg=√((2-2)^2+(-1-1)^2)=√(0+(-2)^2)=2\ units`

The hypotenuse is gotten using Pythagorean theorem. It is gotten by:

Hypotenuse² = (Horizontal leg)² + (Vertical leg)²

Hypotenuse² = 7² + 2²

Hypotenuse² = 49 + 4 = 53

Hypotenuse = √53

Hypotenuse = 7.28 unit