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A ball is released at a height of 16 inches to roll inside a half-cylinder. It rolls

to a height of 8 inches on the other side of the cylinder on roll 1. Each time it
rolls up a side of the cylinder, the ball reaches a point that is as high as it
had reached on the other side.
-lo
This explicit formula models the height of the ball, in inches, the nth time it
rolls up a side of the cylinder.

How high does the ball roll on its 5th time up the cylinder's side?​

A ball is released at a height of 16 inches to roll inside a half-cylinder. It rolls-example-1
User Shinji
by
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1 Answer

1 vote

Answer:

Explanation:

Using the given formula, we put n = 5


h = 8* {((1)/(2)) ^(n-1)

h = 8 / 16

h = 1 / 2 inches

User Anders Arpi
by
6.9k points