Question

2y² +4y-48=0
solve the equation​

Answer 1

y = - 6, y = 4

Explanation:

Given

2y² + 4y - 48 = 0 ( divide through by 2 )

y² + 2y - 24 = 0

Consider the factors of the constant term (- 24) which sum to give the coefficient of the y- term (+ 2)

The factors are + 6 and - 4 , since

6 × - 4 = - 24 and 6 - 4 = + 2 , thus

(y + 6)(y - 4) = 0

Equate each factor to zero and solve for y

y + 6 = 0 ⇒ y = - 6

y - 4 = 0 ⇒ y = 4

Answer 2

Explanation:

2y² + 4y - 48 = 0

2y² + 12y - 8y + (-8)* 6 = 0

2y(y + 6) - 8(y + 6) =0

(y + 6) (2y - 8)= 0

y + 6 = 0 ; 2y- 8 = 0

y = -6 2y = 8

y = 8/2

y = 4

Solution: y = -6 , 4