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The isotope (_90^234)Th has a half-life of 24days and decays to (_91^234)Pa. How long does it take for 90% of a sample of (_90^234)Th to decay to (_91^234)Pa?

User Qris
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2 Answers

3 votes

Final answer:

To calculate how long it takes for 90% of the sample of (_90^234)Th to decay, we use the half-life of 24 days and the formula for exponential decay. Approximately 78.26 days are required for 90% of the isotope to decay to (_91^234)Pa.

Step-by-step explanation:

To calculate how long it takes for 90% of a sample of isotope (_90^234)Th to decay to (_91^234)Pa, we need to understand the concept of half-life. The half-life of (_90^234)Th is 24 days, meaning that every 24 days, half of the remaining sample will decay. To decay 90%, we need to reach a point where only 10% is left un-decayed.

To find the appropriate number of half-lives that correspond to 90% decay, we can use the formula:

N(t) = N0 * (1/2)^(t/T)

Where N(t) is the remaining amount, N0 is the initial amount, t is the time in days, and T is the half-life in days.

For 90% decay, N(t) = 0.10 * N0:

0.10 = (1/2)^(t/24)

We need to solve for t, the time in days:

t/24 = log(0.10) / log(0.5)

t = 24 * log(0.10) / log(0.5)

Calculating the time yields approximately 78.26 days for 90% of the sample to decay.

User Bqubique
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2 votes

Answer:

79.7 days

Step-by-step explanation:

Half-life equation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is the amount of time,

and T is the half life.

If 90% decays, then 10% is left.

A = A₀ (½)^(t / T)

0.1 A₀ = A₀ (½)^(t / 24)

0.1 = ½^(t / 24)

ln(0.1) = (t / 24) ln(0.5)

t ≈ 79.7 days

User Tigran Abrahamyan
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