Question

Volume 1 (3)3 = 367

SSCE/JME-TYPE OF
2
The area of an equilateral triangle of side 8 cm is
A. 16V3 cm? B. 32/3 cm
B.
48 cm
cm?
D.
36V3 cm
A
parallelogram
of area 425 cmhas a height o​

Answer 1

`A.\ 16\sqrt3\ cm^2` is the correct answer.

Explanation:

Given that:

Side of an equilateral triangle = 8 cm

To find:

Area of the triangle will be:

`A.\ 16\sqrt3\ cm^2`

`B.\ (32)/(3) cm^2`

`C.\ 48\ cm^2`

`D.\ 36\sqrt3\ cm^2`

Solution:

First of all, let us have a look at the formula for area of an equilateral triangle:

`A =(\sqrt3)/(4)a^2`

Where
`a` is the side of equilateral triangle and an equilateral triangle is a closed 3 sided structure in 2 dimensions which has all 3 sides equal to each other.

Here, we are given that side,
`a=8\ cm`

Putting the value in formula:

`A =(\sqrt3)/(4)* 8^2\\\Rightarrow A =(\sqrt3)/(4)* 64\\\Rightarrow A =\sqrt3* 16\\OR\\\Rightarrow \bold{A =16\sqrt3\ cm^2}`

Hence,
`A.\ 16\sqrt3\ cm^2` is the correct answer.