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A piece of aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. What is its density of the aluminum rounded to the nearest hundredth? Only enter numerical values, which can include a decimal point.

User Angy
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1 Answer

5 votes

Answer:

6.87 g/mL

Explanation:

The density of an object can be found by dividing the mass by the volume.


density=(mass)/(volume)\\\\ d=(m)/( v)

We know that the aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. Therefore, the mass is 87.3 g and the volume is 12.7 mL.


m= 87.3 g\\\\v=12.7 mL

Substitute the values into the formula.


d= (87.3 g)/(12.7 mL)

Divide 87.3 g by 12.7 mL


d=6.87401575 g/mL

Round to the nearest hundredth. The 4 in the thousandth place tells us to leave the 7 in the hundredth place.


d= 6.87 g/mL

The density of the aluminum is about 6.87 grams per milliliter.

User Abhendra Singh
by
4.9k points
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