Question

Write the polar form of a complex number in standard form for
`8[cos((\pi)/(2)) + isin((\pi)/(2))]`

Answer 1

Solution : 8i

Explanation:

We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,

`8\left[cos\left((\pi )/(2)\right)+isin\left((\pi \:)/(2)\right)\right]` =
`8\left(0+1i\right)`

And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.