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(x-1)(x+2)(x-3)(x+7)(x-5)/2x-2

=0

What can x be?

(x-1)(x+2)(x-3)(x+7)(x-5)/2x-2 =0 What can x be?-example-1

1 Answer

3 votes

Answer:

see below

Explanation:

Multiplying the equation by 2x - 2 on both sides to cancel out the denominator gives us (x - 1)(x + 2)(x - 3)(x + 7)(x - 5) = 0. Using Zero Product Property and setting each factor to 0, we get:

x - 1 = 0 or x + 2 = 0 or x - 3 = 0 or x + 7 = 0 or x - 5 = 0

x = 1, x = -2, x = 3, x = -7, x = 5

Unfortunately, x cannot be 1 as the numerator would become 0 and then the expression on the left side would become undefined so the final answer is x = -2, x = 3, x = 7, x = 5.

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