Question

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is:

Answer 1

`\lambda` = 40 cm

Step-by-step explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L =
`n * (1)/(4) \lambda` ...............1

so

total length will be here

`L = (\lambda)/(2) + (\lambda)/(4)\\`

`L = (3 \lambda )/(4)`

so
`\lambda` will be

`\lambda = (4L)/(3)\\\lambda = (4* 30)/(3)`

`\lambda` = 40 cm