Question

Given the equation 4x−8y=32, a second equation that forms a system with no solution is: 1. x−2y=8 2. x−2y=32 3. x+2y=8 4. 2x−y=32

Answer 1

2. x−2y=32.3

Explanation:

Given 4x - 8y = 32, a second equation that forms a system with no solution is most easily found by reducing the given equation to x - 2y = 8; we can then easily compare this x - 2y = 8 to x - 2y = 32.3. These two lines are parallel and thus do not intercept, and thus the system has no solution.