9.7k views
2 votes
Of a group of boys and girls at Central Middle School’s after-school party, 15 girls left early to play in a volleyball game. The ratio of boys to girls then remaining was 2 to 1. Later, 45 boys left for a football game. The ratio of girls to boys was then 5 to 1. How many students attended the party?

User Bal Chua
by
8.6k points

2 Answers

3 votes

Answer:

let b = original number of boys

let g = original number of girls

:

Of a group of boys and girls at Central Middle School's after-school party, 15 girls left early to play in a volleyball game.

The ratio of boys to girls then remaining was 2 to 1.

b%2F%28%28g-15%29%29 = 2%2F1

Cross multiply

b = 2(g-15)

b = 2g - 30

:

Later, 45 boys left for a football game. The ratio of girls to boys was then 5 to 1.

%28%28g-15%29%29%2F%28%28b-45%29%29 = 5%2F1

cross multiply

g - 15 = 5(b-45)

g - 15 = 5b - 225

g = 5b - 225 + 15

g = 5b - 210

Replace b with (2g-30)

g = 5(2g-30) - 210

g = 10g - 150 - 210

g = 10g - 360

360 = 10g - g

360 = 9g

g = 360/9

g = 40 girls originally

find b

b = 2(40) - 30

b = 50 boys originally

" How many students attended the party?"

40 + 50 = 90 students

User Jmknoll
by
8.3k points
3 votes

Answer:

90

Explanation:

Let g and b represent the number of girls and boys attending, respectively.

After 15 girls left, the ratio of boys to girls was ...

b/(g -15) = 2/1

b = 2g -30 . . . . . multiply by (g-15)

__

After 45 boys left, the ratio of girls to boys was ...

(g -15)/(b -45) = 5/1

g -15 = 5b -225 . . . . . . multiply by (b-45)

g = 5b -210

Using the latter to substitute into the former, we have ...

b = 2(5b -210) -30

450 = 9b . . . . . add 450-b

50 = b . . . . . . 50 boys attended

g = 5(50) -210 = 40 . . . . . 40 girls attended

The number of students who attended the party was 50 +40 = 90.

_____

Check

After 15 girls left, the ratio of boys to girls was 50/25 = 2/1.

After 45 boys left, the ratio of girls to boys was 25/5 = 5/1.

User Jogy
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories