Question

Will the Python code below print something? And will it terminate?

def print_n(s, n):
if n > 0:
print(s)
print_n(s, n-1)
return n
n = 3
while print_n("hi", n):
print_n("there!", n)
n = 0
a. no and no
b. yes and no
c. no and yes
d. yes and yes
e. syntax error

Answer 1

Yes and Yes

Step-by-step explanation:

When programs are written without indentation; it becomes a problem to read;

I'll rewrite your program as follows:

def print_n(s, n):

if n > 0:

print(s)

print_n(s, n-1)

return n

n = 3

while print_n("hi", n):

print_n("there!", n)

n = 0

Using the above as a point of reference,

Yes, the program will run and Yes, it'll terminate;

Because n is initialized to 3 at line 6 (where the main starts);

The following is passed to the function; s = "hi" and n=3

This prints "hi", three times

s = "there" and n=3 is then passed to the function print_n, afterwards;

The function then prints "there" three times

Then, the program terminates