Question

Consider a hydraulic lift that uses an input piston with an area of 0.5m2. An input force of 15N is exerted on this piston. If the output piston has an area of 3.5m? What is the output force?

Answer 1

The output force of the piston is 105 N.

Step-by-step explanation:

Given;

the area of the input piston, A₁ = 0.5 m²

the input force of the piston, F₁ = 15 N

the area of the output piston, A₀ = 3.5 m²

the output force of the piston, F₀ = ?

The pressure of the hydraulic lift is given by;

`P = (F)/(A)`

where;

P is the hydraulic pressure

F is the piston force

A is the area of the piston

`P = (F)/(A) \\\\(F_o)/(A_o) = (F_i)/(A_i) \\\\F_o = (F_iA_o)/(A_i) \\\\F_o = (15*3.5)/(0.5) \\\\F_o = 105 \ N`

Therefore, the output force of the piston is 105 N.