Question

Please solution this question now .thank you very much​

Answer 1

5/2

Explanation:

Let u = sin(t). Then this is the integral ...

`\displaystyle\int_0^{(\pi)/(2)}{5u}\,du=\left.(5u^2)/(2)\right|_0^{(\pi)/(2)}=(5)/(2)(\sin((\pi)/(2))^2-\sin(0)^2)=(5)/(2)(1-0)=\boxed{(5)/(2)}`