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Let s1 = k and define sn+1 = √4sn − 1 for n ≥ 1. Determine for what values of k the sequence (sn) will be monotone increasing and for what values of k it will be monotone decreasing.

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Answer:

The answer is "
\bold{(1)/(4)<k\leq 2+√(3)}"

Explanation:

Given:


\ S_1 = k \\\\ S_(n+1) = √(4S_n -1)
_(where) \ \ n \geq 1

In the above-given value,
S_n is required for the monotone decreasing so,
S_2 :


\to √(4k-1) \leq \ k=S_1\\\\

square the above value:


\to k^2-4k+1 \leq 0\\\\\to k \leq 2+√(3) \ \ \ \ \ and \ \ 4k+1 >0\\\\


\bold{\boxed{(1)/(4)<k\leq 2+√(3)}}

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