Answer:
![\large \boxed{\mathrm{D. \ \displaystyle (7√(2) )/(2 )}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/sfc3x4wcw3r5d2494xmju8fwwmt6manuif.png)
Explanation:
The triangle is a right triangle.
We can use trigonometric functions to solve the problem.
![sin \theta = opp/hyp](https://img.qammunity.org/2021/formulas/mathematics/high-school/gmzhzgzrgoxcv6ho5ks5nnakaemkyysqns.png)
The opposite side to the angle 45 degrees is x and the hypotenuse of the triangle is 7.
![sin 45 = x/7](https://img.qammunity.org/2021/formulas/mathematics/high-school/mh1ts0e9yop2fj6vqheryjg6m4q6091ikz.png)
Multiply both sides of the equation by 7.
![7 sin 45 = x](https://img.qammunity.org/2021/formulas/mathematics/high-school/zpe3y0oglznlvds920pyfj12149m42re3c.png)
Simplify the value.
![\displaystyle (7√(2) )/(2 )=x](https://img.qammunity.org/2021/formulas/mathematics/high-school/w4jy696rhrs4ew35eocdxum1jjzvmvmyhm.png)