Answer:
The time of short pulse of light beam is
![2.37*10^(-9)\ sec](https://img.qammunity.org/2021/formulas/physics/college/pw6pnv4v4qwf12lgx67h6bvt40g5cyzzfx.png)
Step-by-step explanation:
Given that,
A beam of light from a laser illuminates a glass.
Suppose, the length of piece is
![L=25.21*10^(-2)\ m](https://img.qammunity.org/2021/formulas/physics/college/5feft4ydtlue1mp2ngmkbvszmamafnh445.png)
Index of refraction is 2.83.
We need to calculate the speed of light pulse in glass
Using formula of speed
![v=(c)/(\mu)](https://img.qammunity.org/2021/formulas/physics/college/dzgeib84ki2m2jid32sic9k7h6n4o2k9cd.png)
Put the value into the formula
![v=(3*10^(8))/(2.83)](https://img.qammunity.org/2021/formulas/physics/college/dg078jpq2d7iffj4offk0uhau47ct482gf.png)
![v=1.06*10^(8)\ m/s](https://img.qammunity.org/2021/formulas/physics/college/mw9weohyoptkcutupz3mvo7ggkwv3836zz.png)
We need to calculate the time of short pulse of light beam
Using formula of velocity
![v=(d)/(t)](https://img.qammunity.org/2021/formulas/physics/college/yb8yhxfd0dloytbyvzh6g8royin8sowug7.png)
![t=(d)/(v)](https://img.qammunity.org/2021/formulas/physics/college/cwq2qxh5njqmlzqcaa110w0i173l35zgms.png)
Put the value into the formula
![t=(25.21*10^(-2))/(1.06*10^(8))](https://img.qammunity.org/2021/formulas/physics/college/y73bfq5qfb99vh1107b08b0an70s7470s1.png)
![t=2.37*10^(-9)\ sec](https://img.qammunity.org/2021/formulas/physics/college/pr7jebrtata3v3gvzhhlhkj0dzutb8f2ir.png)
Hence, The time of short pulse of light beam is
![2.37*10^(-9)\ sec](https://img.qammunity.org/2021/formulas/physics/college/pw6pnv4v4qwf12lgx67h6bvt40g5cyzzfx.png)