Answer:
Explanation:
Let REPEAT
=
To prove that REPEAT
is undecidable.
Let REPEAT
M is a TM that does not accept M
Then, we form a TM u for L by applying TM v as a subroutine.
Assume Repeat is decidable
Let M be the algorithm that TM which decides the REPEATU = on input "s" simulate the M
Accept; if M ever enters the accept state
Reject; if M ever enters the reject state
U does not decide the REPEAT as it may loop over s
so REPEAT is undecidable